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Q11 REMAINDERS

The remainder when (1523 + 2323) is divided by 19, is 

  a. 4

  b. 15

  c. 0

  d. 18

xn + an) is divisible by (x + a) when n is odd
∴ (15
23 + 2323) is divisible by (15 + 23)
⇒ (15
23 + 2323) is divisible by 38 and hence by 19
⇒ On dividing (15
23 + 2323) by 19, we get 0 as remainder.

  

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