The remainder when (1523 + 2323) is divided by 19, is
a. 4
b. 15
c. 0
d. 18
xn +
an)
is divisible by (x + a) when n is odd
∴ (1523 +
2323)
is divisible by (15 + 23)
⇒ (1523 +
2323)
is divisible by 38 and hence by 19
⇒ On dividing (1523 +
2323)
by 19, we get 0 as remainder.
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