If x = (163 + 173 + 183 + 193), then x divided by 70 leaves a remainder of
a. 0
b. 1
c. 35
d. 69
16^3 + 17^3 + 18^3 + 19^3 = 16^3 + 19^3 + 17^3 + 18^3 is divisible by (16+19)
i.e. 35 and is also divisible by (17+18) i.e. 35 as well.
So, (16^3 + 17^3 + 18^3 + 19^3) = 35x+35y,
as x+y must be even,
hence the given expression is divisible by 70.
So, the remainder will be 0..Write Here