m is the smallest positive integer such that for any integer n > m, the quantity n³-7n^2+11n-5 is positive. What is the value of m?
(a). 4
(b). 5
(c), 8
(d). None of theseOption (d)
n=1 is a root of the equation
(n−1)(n^2−6n+5)=(n−1)(n-1)(n−5)
Now, n−12 is always positive.
Now, for n < 5, the expression gives a negative quantity.
Therefore, the least value of n will be 6. Hence m = 7 .
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