Let
T be the set of integers (3,11,19,27... 451,459,467) and S be a subset of T
such that the sum of no two elements of S is 470. The maximum possible number
of elements in S is

a.
32

b.
28

c.
29

d.
30

No.
of terms in series T , 3+(n-1)*8 = 467 i.e. n=59.

Now S will have atleast
have of 59 terms i.e
29 .

Also
the sum of 29th term and 30th term is less than 470.