Each of the numbers x1, x2,
...... xn ,
n ≥ 4, is equal to 1 or —1. Suppose,
x1 X2 X3 X4 +
X2 X3 X4 X5 +
X3 X4 X5 X6 ...... Xn-3 Xn-2 Xn-1 Xn + Xn-2 Xn-1 Xn X1+ Xn-1Xn X1X2 + Xn X1 X2 X3 =0,
then
a) n is even
b) n is odd
c) n is an odd multiple of 3
d) n is prime
Each term has to be either 1 or –1.
Hence, if the sum of n such terms is 0, then n is even
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