My son adores chocolates. He likes biscuits. But he hates apples. I told him that he can buy as many chocolates he wishes. But then he must have biscuits twice the number of chocolates and should have apples more than biscuits and chocolates together. Each chocolate cost Re 1. The cost of apple is twice the chocolate and four biscuits are worth one apple. Then which of the following can be the amount that I spent on that evening on my son if number of chocolates, biscuits and apples brought were all integers?

a. Rs. 8

b. Rs. 33

c. Rs. 34

d. None of these

Let he bought x chocolates, 2x biscuits and 3x+ y apples

Chocolate price = Re. 1, Apple price = 2 Biscuit price = 1/4 of apple price = 2/4 = 0.5

Amount = x+0.5 x 2x + 2(3x+y)=8x + 2y

Option (a) is not possible as minimum amount = 8 x 1 + 2

x 1 = 10

Option (b) is not possible as the amount 8x + 2y is even

Option (c) is possible if x = 3, y=5.

Hence option (c) is correct.**Write Here**