When 2^256 is divided by 17, the remainder would be
a. 1
b. 16
c. 14
d. None of these2^256 can be written as (2^4)64=(17−1)^64.
In the expansion of (17−1)^64, every term is divisible by 17 except (−1)64. Hence remainder is 1.
Or alternatively:
Euler's number of 17 is 16 and 256 is a multiple of 16. Hence the remainder is 1.
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