Let A and B be two solid spheres such that the surface area of B is 300% higher than the surface area of A. The volume of A is found to be k% lower than the volume of B. The value of k must be
a. 85.5
b. 92.5
c. 90.5
d. 87.5Surface area of sphere A (of radius a) is 4πa²
Surface area of sphere B (of radius b) is 4πb²
4π a²/4π b²=1/4 => a:b=1:2
Therefore, k = 7/8 100% = 87.5%
Their volumes would be in the ratio 1:8Write Here