In a four-digit number, the sum of the first 2 digits is equal to that of the last 2 digits. The sum of the first and last digits is equal to the third digit. Finally, the sum of the second and fourth digits is twice the sum of the other 2 digits. What is the third digit of the number?
a. 5
b. 8
c. 1
d. 4
Let
the 1st,
2nd,
3rd and
4th digits
be a, b, c and d respectively.
Then, a + b = c + d ----------(i) a + d = c ----------(ii ) b + d = 2(a + c)
----------(iii)
from eqn. (i) and (ii),
a + b = a + 2d →b = 2d
and eqn
(iii);
2d + d = 2(a + a + d) → 3d = 2(2a + d)
→ d = 4a or, a = d/4
Now, from eqn. (ii),
a + d = (d/4) + d = 5d/4
Or, c = 5d/4
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