What is the sum of all two digit numbers that give a remainder of 3 when they are divided by 7?

a. 666

b. 676

c. 683

d.77

The
two digit number which gives a remainder of 3 when divided by 7 are:

10, 17, 24 ..... 94.

Now, these number are in AP series with

1st Term, a = 10;

Number of Terms, n = 13;

Last term, L = 94 and

Common Difference, d = 7.

Sum,

={n×(a+L)}/2
= 13×52 = 676

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