What is the sum of all two digit numbers that give a remainder of 3 when they are divided by 7?
a. 666
b. 676
c. 683
d.77
The
two digit number which gives a remainder of 3 when divided by 7 are:
10, 17, 24 ..... 94.
Now, these number are in AP series with
1st Term, a = 10;
Number of Terms, n = 13;
Last term, L = 94 and
Common Difference, d = 7.
Sum,
={n×(a+L)}/2
= 13×52 = 676
Write Here