Train
X departs from station A at 11 a.m. for station B, which is 180 km so far.
Train Y departs from station B at 11 a.m. for station A. Train X travels at an
average speed of 70 km/hr
and does not stop anywhere until it arrives at station B. Train Y travels at an
average speed of 50 km/hr,
but has to stop for 15 min at station C, which is 60 km away from station B enroute
to station A. Ignoring the lengths of the trains, what is the distance, to the
nearest kilometre,
from station A to the point where the trains cross each other?

a. 112 km

b. 118 km

c. 120 km

d. None of these

Distance
between A-B, A-C, C-B is 180, 120 and 60 km respectively.

Let x be the distance from A where the 2 trains meet.

According to given condition we have

x/70 = (60/50) + (1/4) + (120-x/50)

Solving the equation we get x around 112 km.

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