Home >> TIME, SPEED AND DISTANCE >> tsd-q18

TSD Q18

Train X departs from station A at 11 a.m. for station B, which is 180 km so far. Train Y departs from station B at 11 a.m. for station A. Train X travels at an average speed of 70 km/hr and does not stop anywhere until it arrives at station B. Train Y travels at an average speed of 50 km/hr, but has to stop for 15 min at station C, which is 60 km away from station B enroute to station A. Ignoring the lengths of the trains, what is the distance, to the nearest kilometre, from station A to the point where the trains cross each other?
a. 112 km
b. 118 km

       c. 120 km
d. None of these 

Distance between A-B, A-C, C-B is 180, 120 and 60 km respectively.
Let x be the distance from A where the 2 trains meet.
According to given condition we have
x/70 = (60/50) + (1/4) + (120-x/50)
Solving the equation we get x around 112 km.

Write Here

Video Explanation

Share the solution with your mates: