If
a man cycles at 10 km/hr,
then he arrives at a certain place at 1 p.m. If he cycles at 15 km/hr,
he will arrive at the same place at 11 a.m. At what speed must he cycle to get
there at noon?
(a) 11 km/hr
(b) 12 km/hr
(c) 13 km/hr
(d) 14 km/hr
When speed of the man = 10 km/hr = d/t
When speed of the man = 15 km/hr = d/(t-2)
Equating the value of d,
10 × t = 15 × (t - 2)
t = 6 hours.
Desired speed = d/(t-1) = 10t/(t-1) = 12
The correct option is B.
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